SOLUTION: Find y-intercept and vertex y = x^2 - 3x - 4

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Question 91110: Find y-intercept and vertex y = x^2 - 3x - 4
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
To find the y-intercept, plug in x=0

Lets find the value of y when

Start with the given polynomial


Plug in


Raise 0 to the second power to get 0


Multiply 3 by 0 to get 0


Remove any zero terms


So when ,

So the y-intercept is (0,-4)


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To determine the x-value of the vertex, use this formula


From the equation we can see that a=1 and b=-3

Plug in b=-3 and a=1


Negate -3 to get 3


Multiply 2 and 1 to get 2

Reduce



So the x-coordinate of the vertex is (which is in decimal form). Lets plug this into the equation to find the y-coordinate of the vertex.


Lets evaluate

Start with the given polynomial


Plug in


Raise 1.5 to the second power to get 2.25


Multiply -3 and 1.5 to get -4.5


Now combine like terms


So the vertex is (1.5,-6.25)


Here is a graph to see the vertex and y-intercept


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