SOLUTION: I have trouble with word problems like the following.... A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30ft by 40ft. The tot

Question 90880This question is from textbook Beginning Algebra
: I have trouble with word problems like the following....
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30ft by 40ft. The total area, garden plus walkway, is to be 1800ft^2. What must be the width of the walkway to the nearest thousandth?
I honestly don't even know where to beginning??? This question is from textbook Beginning Algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
This same problem came up a short time ago. Here is what I submitted then.
:
A rectangular garden is to be surrounded by a walkway of constant width. The garden's dimensions are 30ft by 40ft. The total area, garden plus walkway, is to be 1800ft^2. What must be the width of the walkway to the nearest thousandth?
:
Let x = width of the walkway
:
Draw this out labeling the walkway width as x, and the inner rectangle
representing the garden as 30 by 40. It will be apparent that the overall
dimensions will be (2x+30) by (2x+40), the area of that is given as 1800 sqft
:
(2x + 30) * (2x + 40) = 1800
:
FOIL
4x^2 + 140x + 1200 = 1800
:
4x^2 + 140x + 1200 - 1800 = 0
:
4x^2 + 140x - 600 = 0
:
Simplify, divide eq by 4 and you have:
x^2 + 35x - 150 = 0
:
Use the quadratic formula to find x: a=1; b=35; c=-150

:
Do the math and you will get two solutions; -38.86 and +3.86,
obviously it's x = 3.86
:
3.86 ft is the width of the walkway
:
:
Check it:
2x = 2(3.86) = 7.72
So we have:
37.72 * 47.72 = 1799.998 ~ 1800 sq ft
:
How about this? Did it make sense to you? Any questions?
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