SOLUTION: Determine if the relation is a function. {{{x^2=1+y^2}}}

Question 90609: Determine if the relation is a function.

Answer by mathispowerful(115) (Show Source): You can put this solution on YOUR website!

solve for y:
y = +/-
you can see that for each x value, there will be 2 y values, that means y value
is not unique, according to the definition of function, it is not a function.
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