SOLUTION: Give the center of the circle with equation x squared+2x+y squared+22=0

SOLUTION: Give the center of the circle with equation x squared+2x+y squared+22=0

Algebra.Com

Question 90264This question is from textbook
: Give the center of the circle with equation x squared+2x+y squared+22=0 This question is from textbook

Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
X^2+2X+Y^2+22=0
Y^2=X^2-2X-22=0
(graph 300x200 pixels, x from -6 to 15, y from -20 to 20, y = sqrt(x^2 -2x -22)).
RELATED QUESTIONS
Give the center of the circle with equation x squared+2x+y... (answered by Earlsdon)

GIVE THE CENTER OF THE CIRCLE WITH EQUATION... (answered by funmath)

Give the center of the circle with the equation x^2 + 2x + y^2 - 10y + 22 =... (answered by stanbon)

Give the center of the circle with equation x^2+2x+y^2-10y+22=0. Thank... (answered by jake_6233)

find the center and radius of the circle with equation X(squared)+(y-8)(squared)=81.... (answered by solver91311)

i have to find the center of a circle with an equation (x-2)squared+(y+3)squared=16 (answered by mathslover,edjones)

I need help finding the radius and center of a circle with the following equation x... (answered by mukhopadhyay)

Give the center of the circle with equation x^2+2x+y^2+22=0 I�ve come up with the answer (answered by psbhowmick,chitra)

Find the center and radius of each circle. Then graph the circle. x squared + y squared + (answered by Fombitz)