SOLUTION: the length of a closed box is 3 times its height, and it is 4 cm wide. if the total surface area is 88 cm^2, find the dimensions of the box.

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Question 902637: the length of a closed box is 3 times its height, and it is 4 cm wide. if the total surface area is 88 cm^2, find the dimensions of the box.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
.
Surface = 2lw + 2lh + 2wh
Surface = 2(3h)4 + 2(3h)h + 2*4h = 88cm^2
6h^2 + 24h + 8h -88 = 0
6h^2 + 32h - 88 = 0
3h^2 + 16h - 44 = 0 (Tossing out the negative solution for unit measure)
h = 2cm
l = 6cm
w = 4cm
Surface = 2lw + 2lh + 2wh = 48 + 24 + 16 = 88
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=784 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2, -7.33333333333333. Here's your graph:

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