SOLUTION: Algebraically find the the vertex y=6+x-x^2 I know how to find vertex, i am just confused if c=6 b=x a=-x^2 or do i have to change the equation to make it positive like x^2-x-6

SOLUTION: Algebraically find the the vertex y=6+x-x^2 I know how to find vertex, i am just confused if c=6 b=x a=-x^2 or do i have to change the equation to make it positive like x^2-x-6

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Question 902187: Algebraically find the the vertex
y=6+x-x^2
I know how to find vertex, i am just confused if c=6 b=x a=-x^2 or do i have to change the equation to make it positive like x^2-x-6 instead. Not sure if that makes a difference.
Thanks in advance

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
y = -x^2 + x + 6 |Completing the Square
y = -(x - .5)^2 + 6.25 V(-.5, 6.25) Parabola Opening Downward
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