The first thing, when factoring this trinomial is to factor out the GCF, which is 8. 

Thus,  becomes: , after which,  should be factored.

Final factors: 



It's confusing when c is the variable in the trinomial, so it's better to 

change  to ....same thing, just that the variable was changed from c to x.

Without factoring out a GCF, and applying the "ac" method, we would need two factors with a product

of - 1,152 (a * c, or 72 * - 16), and that SUM to "b" (+ 24). These factors are: + 48 and - 24.

We now replace + 24x in the trinomial,  with + 48x - 24x. I hope you're following!!



Now,  becomes: . At this point, I'd switch the variable, x back to c,

so we now have: 



The factors are now obtained by grouping the first two binomials, and then the last two binomials, so that results in: 

, and the final answer: , which is the same as your factors: .

Factoring these further, results in: , the CORRECT factors.



However,  and  are incorrect as the GCF of the original polynomial should be obtained

and factored out first. I only went this far to explain the procedure to determine the correct factors when

leading-coefficient multiples such as 24, 36, 72, and others are part of polynomials that need to be factored.

These and other leading-coefficient multiples pose a problem at times since they have as many as 4 or 5 sets of

factors, and can be pretty tedious to factor correctly. 

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 In the quadratic equation



1.  72c2 + 24c - 16

---------------

That's not an equation, there's no equal sign.

The answer is (12c - 4) (6c + 4)

------------

I would say it's 8*(3c-1)*(3c+2)

-------

The short answer is, because 9 and 8 don't work.  If you factor out the 8 first, it's obvious it can't be 9 and 8.



Then you might ask, "Why 3 and 3, and not 9 and 1?"

You can't get the middle term to be 3c using 9 and 1.

-------

Factor out any coefficients first, it'll make it simpler.

Use ^ (Shift 6) for exponents.

eg, c^2 

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
 


 
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


 Start with the given expression.



 Factor out the GCF .



Now let's try to factor the inner expression 



---------------------------------------------------------------



Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .



Now multiply the first coefficient  by the last term  to get .



Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient ?



To find these two numbers, we need to list all of the factors of  (the previous product).



Factors of :

1,2,3,6,9,18

-1,-2,-3,-6,-9,-18



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to .

1*(-18) = -18
2*(-9) = -18
3*(-6) = -18
(-1)*(18) = -18
(-2)*(9) = -18
(-3)*(6) = -18


Now let's add up each pair of factors to see if one pair adds to the middle coefficient :



First Number
Second Number
Sum
1
-18
1+(-18)=-17
2
-9
2+(-9)=-7
3
-6
3+(-6)=-3
-1
18
-1+18=17
-2
9
-2+9=7
-3
6
-3+6=3




From the table, we can see that the two numbers  and  add to  (the middle coefficient).



So the two numbers  and  both multiply to  and add to 



Now replace the middle term  with . Remember,  and  add to . So this shows us that .



 Replace the second term  with .



 Group the terms into two pairs.



 Factor out the GCF  from the first group.



 Factor out  from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



 Combine like terms. Or factor out the common term 



--------------------------------------------------



So  then factors further to 



===============================================================



Answer:



So  completely factors to .



In other words, .



Note: you can check the answer by expanding  to get  or by graphing the original expression and the answer (the two graphs should be identical).


 

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