SOLUTION: X-INTERCEPTS AND VERTEX TO X^2+10X+22

SOLUTION: X-INTERCEPTS AND VERTEX TO X^2+10X+22

Algebra.Com

Question 900106: X-INTERCEPTS AND VERTEX TO X^2+10X+22
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
To get to vertex form, complete the square.

The vertex is (-5,3).
Now to find the zeros set it equal to zero.

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