SOLUTION: Solve by using the quadratic formula. 5x^2 + x = 3

Question 89362: Solve by using the quadratic formula.
5x^2 + x = 3

Found 2 solutions by jim_thompson5910, malakumar_kos@yahoo.com:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Subtract 3 from both sides

Now let's use the quadratic formula to solve for x:

Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )

Plug in a=5, b=1, and c=-3

Square 1 to get 1

Multiply to get

Combine like terms in the radicand (everything under the square root)

Simplify the square root (note: If you need help with simplifying the square root, check out this solver)

Multiply 2 and 5 to get 10

So now the expression breaks down into two parts

or

Now break up the fraction

or

So these expressions approximate to

or

So our solutions are:
or

Notice when we graph , we get:

when we use the root finder feature on a calculator, we find that and .So this verifies our answer
Answer by malakumar_kos@yahoo.com(315) (Show Source): You can put this solution on YOUR website!

Solve by using the quadratic formula.
5x^2 + x = 3
5x^2+x-3 = 0 compare with the std form ax^2+bx+c= 0
we get a= 5, b = 1 and c= -3
the std formula is AMP Parsing Error of [x = (-b+-sqrt(b^2-4ac))/2*a*]: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .

x = (-1+-sqrt(1^2-4*5*-3)/2*5
= {-1+-sqrt(1+60)}/10
= {-1+-sqrt(61)}/10
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