SOLUTION: I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.  The value of the discriminant is 169.  There are 2 real roots.  There are 2

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Question 887128: I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.
 The value of the discriminant is 169.
 There are 2 real roots.
 There are 2 irrational roots.
 The graph intersects the y-axis twice.
 The parabola is directed upward.
 The axis of symmetry is located at x=-7/4
 The vertex is located at: (-7/4, -49/8)
 The roots are: (5,3/2)
 The graph intersects the y axis at (0, -15).
 The graph intersects the x-axis at (-5, 0) and (1.5, 0)
HELP PLEASE
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Many of the questions depend on the discriminant.

Discriminant is .
What do you understand about the discriminant for a quadratic expression?

Something about the discriminant indicates that your quadratic expression is factorable.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
I. Given the following polynomial: 2x^2+7x-15=0 . Check all that apply.
 The value of the discriminant is 169.
 There are 2 real roots.
 There are 2 irrational roots.
 The graph intersects the y-axis twice.
 The parabola is directed upward.
 The axis of symmetry is located at x=-7/4
 The vertex is located at: (-7/4, -49/8)
 The roots are: (5,3/2)
 The graph intersects the y axis at (0, -15).
 The graph intersects the x-axis at (-5, 0) and (1.5, 0)
HELP PLEASE


, or



 



  The value of the discriminant is 169. Discriminant: , or ___49 + 120 = 169 (CHECK)   

  There are 2 real roots. Since the value of DISCRIMINANT (169) > 0, then there are 2 REAL roots. (CHECK)

  There are 2 irrational roots. Since the value of the DISCRIMINANT (169) is a perfect square (), roots

   are RATIONAL (NO CHECK)

  The graph intersects the y-axis twice. Substituting 0 for x in  results in y being – 15. The

   graph has a sole y-intercept, at – 15 (NO CHECK)

  The parabola is directed upward. Since a > 0, the parabola opens upwards. (CHECK)

  The axis of symmetry is located at x = . Axis of symmetry is at , or , or  (CHECK)  

  The vertex is located at: (, ). Substituting  for x in  produces: , 

   or , or , or , or  (NO CHECK) 

  The roots are: (5,3/2)____ factors to (2x - 3)(x + 5) = 0, so roots are:  and  (NO CHECK)

  The graph intersects the y axis at (0, -15). The y-intercept was found to be – 15, so y-intercept is (0, - 15). 

   This is a CHECK. 

  The graph intersects the x-axis at (-5, 0) and (1.5, 0). As seen above, roots are , so the graph

   intersects the x-axis at (, ) and (, ). This is a CHECK. 

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