SOLUTION: please help me to solve this equation; 2x^2-x<0

Question 885468: please help me to solve this equation; 2x^2-x<0
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
set the equation equal to 0 and solve for x.
you get:
2x^2 - x = 0
factor out an x to get:
x * (2x - 1) = 0
x will be equal to 0 or x will be equal to 1/2.
evaluate the equation when x is less than 0.
you will find that 2x^2 - x is positive.
evaluate the equation when x is greater than 1/2.
you will find that 2x^2 - x is positive.
evaluate the equation when x is greater than 0 and less than 1/2.
you will find that 2x^2 - x is negative.
the expression os 2x^2 - x is less than 0 when x is greater than 0 and less than 1/2.
a grph of your equation is shown below:
$$$

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