SOLUTION: I cannot figure out how to solve this quadratic equation. Solve for x: 2x^2 + 3bx + b^2 = 0 Thank you, Melody Salzer

Question 88446: I cannot figure out how to solve this quadratic equation.
Solve for x:
2x^2 + 3bx + b^2 = 0
Thank you,
Melody Salzer
Found 3 solutions by stanbon, Earlsdon, checkley75:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solve for x:
2x^2 + 3bx + b^2 = 0
------------
Use the quadratic formula to get:
x = [-3b+-sqrt(9b^2-4*2*b^2)]/4
x = [-3b +-sqrt(b^2)]/4
x = [-3b+-b]/4
x = -b or x = -b/2
==================
Cheers,
Stan H.
Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Well, you can always use the quadratic formula to solve a quadratic equation:
But just to make it a little less confusing, we'll write your equation like this, with a B instead of a b:
so...a = 2, b = 3B, and c = B^2
Now, making the appropriate substitutions, we get:
Simplifying this, we have:

So the roots are:
or
or
or
But remember that we substituted the b in the original equation with B, so the answers are:
or
Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!
2x^2+3bx+b^2=0
using the quadratic equation we get:
x=(-3b+-sqrt[(3b)^2-4*2*b^2])/2*2
x=-3b+-sqrt[9b^2-8b^2])/4
x=(-3b+-sqrtb^2)/4
x=(-3b+-b)/4
x=(-3b+b)/4
x=-2b/4
x=-b/2 answer
x=(-3b-b)/4
x=-4b/4
x=-b answer.
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