SOLUTION: complete the square x^2-14x=51 x= ? and ?

Question 87887: complete the square
x^2-14x=51
x= ? and ?
Found 2 solutions by rapaljer, stanbon:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!

Assuming that the coefficient of is 1, you must take HALF of the x coefficient and SQUARE it, adding this quantity to each side of the equation as follows:
Half of -14 is -7, and (-7)^2= 49!

Take the square root of each side:

Add +7 to each side:

By the way, since this came out to a square root of a perfect square, like 100, it means that the problem could have been solved by factoring!!

R^2 Retired from SCC

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
complete the square
x^2-14x=51
x^2-14x+(14/2)^2 = 51+(14/2)^2
(x-7)^2 = 51 + 49
x-7 = +-10
x= 10+7= 17 or x= -10+7=-3
====================
Cheers,
Stan H.
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