SOLUTION: x^2 + 19x + 92 = whole square of an integer when x is integer
find x
Attempted-
let a be the integer
x^2+19x+92-a^2=0
Discriminant>=0
361-4(92-a^2)>=0
4a^2>=7
a^2>=4/7
a<=
Algebra.Com
Question 878715: x^2 + 19x + 92 = whole square of an integer when x is integer
find x
Attempted-
let a be the integer
x^2+19x+92-a^2=0
Discriminant>=0
361-4(92-a^2)>=0
4a^2>=7
a^2>=4/7
a<=-sqrt(7)/4 and a>=sqrt(7)/4
but a is integer
therefore a<=-2 or a>=2
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
(I had posted something here but removed it - please excuse, and repost)
RELATED QUESTIONS
x^2 + 19x + 92 = whole square of an integer when x is integer
find... (answered by AnlytcPhil)
The sum of 2 consecutive odd integers is 92. Find the numbers.
If x represents the... (answered by josmiceli)
The difference of the squares of two positive consecutive even integers is 92. Find the... (answered by josgarithmetic)
Find the value of n such as x^2-19x+n is a perfect square... (answered by checkley77)
if (x+3)/2 is an integer, then x must be
A. a negative integer
B. a positive integer
(answered by Edwin McCravy)
x^2=19x (answered by ikleyn)
x^2-19x+70=0
(answered by jim_thompson5910)
Let x be an integer that satisfies x^4 + 24 = 105. What is the value of x^2 −... (answered by jsmallt9)
let k be an integer and p is a prime such that the quadratic equation x^2+kx+p=0 has two... (answered by ankor@dixie-net.com)