SOLUTION: Dear Math Tutor, How does 3x^2-5x-6=0 become 1/6(5 plus-minus the square root of 97)and x^2-4x-7=0 become 2 plus-minus the square root of 11? with gratitude, Nat

Question 878375: Dear Math Tutor,
How does 3x^2-5x-6=0 become 1/6(5 plus-minus the square root of 97)and
x^2-4x-7=0 become 2 plus-minus the square root of 11?

with gratitude,
Nat

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
You can complete the square or use the quadratic formula.
Quadratic formula:

.
.
.
Completing the square:

RELATED QUESTIONS
Dear Math Tutor, Please help me with: The square root of 162x^6 - the square root of... (answered by ewatrrr)

I need some help describing and correcting the error. 3/x + 6/x+3 =8/x+1... (answered by stanbon,TeachMath)

shit man what is 3x plus 2x minus 7x plus 7x minus 2x equals 9 plus 2x minus 3x plus two... (answered by stanbon)

solve (x-5)^2=7 A)-5+(minus underneath the plus) square root of 7 B) 5+(minus... (answered by tutorcecilia)

(2 minus the square root of 6)(1 plus the sqare root of 6) (answered by checkley77)

Solve quadratic equation: x^2+3x+5=0 a. -3 plus minus i square root 29 over 2... (answered by MORUPHOSUOLALE)

how do i solve the square root of 3x-3 minus the square root of x plus 5 =... (answered by lwsshak3)

Which one of the following does not find the value of f ′(2) for f(x) = x2 + 3x +... (answered by KMST)

Simplify: Question 1: 3 square root of 2 (8 plus square root 5) Question 2: 7 (answered by shree840)