LetThen So substitute for and for 6u - 13 = 0; 2u - 5 = 0 6u = 13 2u = 5 u = u = For u = , since Multiply through by 6x (3x-2)(2x-3) = 0 3x-2 = 0; 2x-3 = 0 3x = 2; 2x = 3 x = ; x = ------ For u = , since Multiply through by 2x (2x-1)(x-2) = 0 2x-1 = 0; x-2 = 0 2x = 1; x = 2 x = ; So there are four solutions: x = x = x = x = 2 Edwin