SOLUTION: A rectangle is 4 feet longer than it is wide, and its area is 20 square feet. Find its dimension to the nearest tenth of a foot.

Question 876711: A rectangle is 4 feet longer than it is wide, and its area is 20 square feet. Find its dimension to the nearest tenth of a foot.
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
set W = width
set L = W + 4
area = L*W
20 = (W + 4)(W)
20 = W^2 + 4W
add -20 to each side
0 = W^2 + 4W -20
Using quadratic equation we get
W = or
Since we need a positive length, the answer is
= 2.90 ft
Let's see if this reasonable.
W = 2.90 , L = 2.90 + 4 = 6.90
2.90 * 6.90 = 20.01 , so we are good
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