SOLUTION: 66x^2 + 67x + 10 =0 Solve followig the square root method or the quadratic formula. Confused on how to work this out any help will be appriciated.

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Question 87558: 66x^2 + 67x + 10 =0
Solve followig the square root method or the quadratic formula.
Confused on how to work this out any help will be appriciated.

Found 3 solutions by checkley75, rapaljer, stanbon:
Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!
66x^2+67x+10=0using the quadratic equation we get:

x=(-67+-sqrt[67^2-4*66*10])/2*66
x=(-67+-sqrt[4489-2640])/132
x=(-67+-sqrt[1849])/132
x=(-67+-43)/132
x=(-67+43)/132
x=24/132
x=.18181818 answer.
x=(-67-43)/132
x=110/132
x=.833333 answer.

Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
This one looks intimidating, when you apply the quadratic formula. Actually, it's not so bad, once you get past the !


a=66, b=67, c=10





or
or

Of course, this means that the problem could have been solved by factoring!!


Another really interesting problem!!

R^2 Retired from SCC

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
66x^2 + 67x + 10 =0
Solve followig the square root method or the quadratic formula.
----------
If you look at the discriminant you get b^2-4ac = 1849
Then sqrt 1849 = 43
Then (-67+-43)/[2*66]
x = -2/11 or x = -5/6
===============
Cheers,
Stan H.

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