SOLUTION: I'm having difficulties with this word problem. Any help that you can give me would be wonderful! Thank you in advance!! The length of a rectangle is 1cm longer than its width.

Question 87295: I'm having difficulties with this word problem. Any help that you can give me would be wonderful! Thank you in advance!!
The length of a rectangle is 1cm longer than its width. If the diagonal of the rectangle is 4cm, what are the dimensions (the length and width) of the rectangle?
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
X^2+(X+1)^2=4^2
X^2+X^2+2X+1=16
2X^2+2X+1-16=0
2X^2+2X-15=0
USING THE QUADRATIC EQUATION THUS:
X=(-2+-SQRT[2^2-4*2*-15])/2*2
X=(-2+-SQRT[4+12])/4
X=(-2+-SQRT124)/4
X=(-2+11.14)/4
X=9.14/4
X=2.285 ANSWER.

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