SOLUTION: Find the real or imaginary solutions by using the quadratic formula. 2x^2+4x=-1

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Question 869811: Find the real or imaginary solutions by using the quadratic formula. 2x^2+4x=-1
Found 3 solutions by mananth, Fombitz, ewatrrr:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!

compare with
a= 2 , b= 4 , c= 1

b^2-4ac= 16 + -8
b^2-4ac= 8



x1=( -4 + 2.83 )/ 4
x1= -0.29

x2=( -4 -2.83 ) / 4
x2= -1.71

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi

2x^2+4x + 1 = 0     ax^2 + x + c  Format









 x = -1 ± .5√2 

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