SOLUTION: The equation of a curve is given by y = 6x^5+12 Obtain the tangent line to the curve at the point where x = 3. Please enter your answer as an equation in the form: y = m x +

Question 869493:
The equation of a curve is given by
y = 6x^5+12
Obtain the tangent line to the curve at the point where x = 3. Please enter your answer as an equation in the form: y = m x + c
for some constants m, c.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Find derivative and then compute this a the slope using x=3.

value of derivative there, is .

Find the y value at x=3 so you know what point this tangent line intersects.

Find the y-intercept for the tangent line at point (3, 1470).

solve for b using the point.

I used "b" instead of "c".

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