SOLUTION: Hi, I am working on a quadratic equation: x^2 + 4x + 4 = 7. I'm not sure if I've arrived at the correct answer...I have x = 2(plus/minus) sq.rt. 7....am I correct in thinking

Question 86765: Hi,
I am working on a quadratic equation: x^2 + 4x + 4 = 7.
I'm not sure if I've arrived at the correct answer...I have x = 2(plus/minus) sq.rt. 7....am I correct in thinking this is the final answer?
Thank you!
Found 2 solutions by Earlsdon, tutorcecilia:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You are almost absolutely correct! The two in your answer should be negative.
Starting with:
Subtract 7 from both sides to get your equation into the standard form:
Applying the quadratic formula: you'll get:
Simplifying this:

Simplifying further:

This should show + or -
or
Answer by tutorcecilia(2152) (Show Source): You can put this solution on YOUR website!
x^2 + 4x + 4 = 7
x^2 + 4x + 4-7 = 7-7
x^2 + 4x -3=0
.

.

.

.

.

.
[factor out a (2)
.
[cancel out]
.
[this form is acceptable for the final answer, but be sure to check your answer]
.
check by plugging the x's back into the orginal formula and solving.
.

x= 0.64575
x^2 + 4x + 4 = 7
(0.64575)^2 + 4(0.64575) + 4 = 7
6.999 = 7 [close enough]
.
and
.

x=-4.6457
(-4.6457)^2 + 4(-4.6457) + 4 = 7
6.999 = 7 [also, close enough]
.

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