SOLUTION: Please help...my original problem is: 2(x-5)^2 = 3. I think the answer is: x= 10 (plus/minus) sq.rt.6 / 2....am I on the right track? Thank you for your help!

SOLUTION: Please help...my original problem is: 2(x-5)^2 = 3. I think the answer is: x= 10 (plus/minus) sq.rt.6 / 2....am I on the right track? Thank you for your help!

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Question 86764: Please help...my original problem is: 2(x-5)^2 = 3.
I think the answer is: x= 10 (plus/minus) sq.rt.6 / 2....am I on the right track?
Thank you for your help!
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
If you are saying that the answer is:
.

.
You are correct.

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