SOLUTION: g(x)=9-2x^2
use the discriminant to determine whether the function has complex zeros
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Question 865160: g(x)=9-2x^2
use the discriminant to determine whether the function has complex zeros
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Real numbers are complex by definition, so g(x) has complex zeros.
Rewriting g(x) as -2x^2 + 0x + 9, the discriminant is 0^2 - 4(-2)(9) > 0, so the complex roots of g are also real (x = +/- sqrt(9/2)).
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