SOLUTION: Find the quadratic function that fits the data points for(-1,0) (3,0) (5,3)

Question 863843: Find the quadratic function that fits the data points for(-1,0) (3,0) (5,3)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the quadratic function that fits the data points for(-1,0) (3,0) (5,3)
------------------------
Form::
ax^2 + bx + c = y
-----
Using (-1,0) you get a - b + c = 0
Using (3,0) you get 9a + 3b + c = 0
Using (5,3) you get 25a + 5a + c = 3
--------------------------------------------
Use any method you know to solve the system:
a = 1/4
b = -1/2
c = -3/4
-----
Equation:
y = (1/4)x^2 -(1/2)x -(3/4)
===================================
Cheers,
Stan H.
RELATED QUESTIONS
Find the quadratic function that fits the data points (1,6) (-1,2) and... (answered by ankor@dixie-net.com,MathTherapy,Alan3354)

Find the quadratic function that fits the set of data points. (-3,-5), (-2,-8),... (answered by stanbon)

Find a quadratic function that fits the set of data points.(0,−3),... (answered by josgarithmetic)

find a quadratic function that fits the set of data points (2,0) (4,3)... (answered by ewatrrr)

Find a quadratic function that fits the set of data points:... (answered by ankor@dixie-net.com)

Find the quadratic function that fits the data points (0,0), (6,0) and... (answered by josmiceli)

find a quadratic function that fits each set of data points (-1, 4) ( 0,4) (4,84) (answered by stanbon)

Find the quadratic equation that fits the data points (3,0) (4,2)... (answered by Fombitz)

Find the quadratic Equation that fits the following set of Data points.... (answered by ankor@dixie-net.com)