SOLUTION: The area of a rectangle is represented by (X^2+10x-56). If the length of the rectangle is (x-4), what would the width be?

SOLUTION: The area of a rectangle is represented by (X^2+10x-56). If the length of the rectangle is (x-4), what would the width be?

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Question 861951: The area of a rectangle is represented by (X^2+10x-56). If the length of the rectangle is (x-4), what would the width be?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
You understand that for a rectangle, , so you can use this in the form of .
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