SOLUTION: Find the axis of symmetry... 1. y=-x^2+4x+2 2. y=x^2+x+1 Find the x-intercepts... 1.y=x^2+2x-8 2. y=x^2-5x-10

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Question 86122: Find the axis of symmetry...
1. y=-x^2+4x+2
2. y=x^2+x+1
Find the x-intercepts...
1.y=x^2+2x-8
2. y=x^2-5x-10

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
1.
Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form


Start with the given equation



Subtract from both sides



Factor out the leading coefficient



Take half of the x coefficient to get (ie ).


Now square to get (ie )





Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation




Now factor to get



Distribute



Multiply



Now add to both sides to isolate y



Combine like terms




Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and "a" is the stretch/compression factor.




Check:


Notice if we graph the original equation we get:


Graph of . Notice how the vertex is (,).



Notice if we graph the final equation we get:


Graph of . Notice how the vertex is also (,).



So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.






2.
Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form


Start with the given equation



Subtract from both sides



Factor out the leading coefficient



Take half of the x coefficient to get (ie ).


Now square to get (ie )





Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation




Now factor to get



Distribute



Multiply



Now add to both sides to isolate y



Combine like terms




Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and "a" is the stretch/compression factor.




Check:


Notice if we graph the original equation we get:


Graph of . Notice how the vertex is (,).



Notice if we graph the final equation we get:


Graph of . Notice how the vertex is also (,).



So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.






We can find the x-intercepts by the quadratic formula
1.
Starting with the general quadratic



the general form of the quadratic equation is:



So lets solve

Plug in a=1, b=2, and c=-8



Square 2 to get 4



Multiply to get



Combine like terms in the radicand (everything under the square root)



Simplify the square root



Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

or

Lets look at the first part:

Add the terms in the numerator
Divide

So one answer is

Now lets look at the second part:

Subtract the terms in the numerator
Divide

So another answer is


So our solutions are:
or

Notice when we graph we get:



and we can see that the roots are and . This verifies our answer

2.
Starting with the general quadratic



the general form of the quadratic equation is:



So lets solve

Plug in a=1, b=-5, and c=-10



Square -5 to get 25



Multiply to get



Combine like terms in the radicand (everything under the square root)



Simplify the square root



Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

or


Which approximate to

or


So our solutions are:
or

Notice when we graph we get:



when we use the root finder feature on our calculator, we find that and .So this verifies our answer

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