SOLUTION: the width of a rectangular parking lot is 57 ft less than its length. determine the dimensions of the parking lot if it measures 250 ft diagonally.

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Question 860158: the width of a rectangular parking lot is 57 ft less than its length. determine the dimensions of the parking lot if it measures 250 ft diagonally.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Let x represent length. Then width is (x-57)
x^2 + (x-57)^2 = 62500
2x^2 - 114x + 3249 = 62500
2x^2 - 114x -59251 = 0
~203ft by 146
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=487004 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 202.964179704603, -145.964179704603. Here's your graph:


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