Hi,
Let x represent the original number of students in group
|Multiplying thru by x(x+2) so as all denominators = 1
120(x+2) - 2x(x+2) = 120x
120x + 240 - 2x^2 - 4x = 120x
2x^2 + 4x - 240 = 0
x^2 + 2x - 120 = 0 (Tossing out the negative solution for unit measure)
(x +12)(x-10) = 0
x = 10, the original number of students in group
CHECKING our answer***
$12 - $2 = $120/12 = $10
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