SOLUTION: How do you factor 5x^2+4x-96=0?

Question 859522: How do you factor 5x^2+4x-96=0?
Found 2 solutions by Fombitz, rothauserc:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Complete the square.

and
So then

and

So,

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
First write down the prime factors of 96
2*48
2*2*24
2*2*2*12
2*2*2*2*6
2*2*2*2*2*6
from the list we see that 2*2*24 or 4*24 satisfies our factorization
5x^2+4x-96 = (5x+24)*(x-4) = 0

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