SOLUTION: if the quadratic formula is used to find the roots of the equation x2 - 6x - 19 =0 ((the 2 is the second power)) the correct roots are?

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Question 858471: if the quadratic formula is used to find the roots of the equation x2 - 6x - 19 =0 ((the 2 is the second power))
the correct roots are?

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: Quadratic Formula
Let's use the quadratic formula to solve for x:


Starting with the general quadratic





the general solution using the quadratic equation is:







So lets solve ( notice , , and )





Plug in a=1, b=-6, and c=-19




Negate -6 to get 6




Square -6 to get 36 (note: remember when you square -6, you must square the negative as well. This is because .)




Multiply to get




Combine like terms in the radicand (everything under the square root)




Simplify the square root (note: If you need help with simplifying the square root, check out this solver)




Multiply 2 and 1 to get 2


So now the expression breaks down into two parts


or



Now break up the fraction



or



Simplify



or



So the solutions are:

or



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