SOLUTION: Find 3 odd consecutive intergers such that the product of the first and third minus the middle intergers is 338.

Question 858210: Find 3 odd consecutive intergers such that the product of the first and third minus the middle intergers is 338.
Answer by ramkikk66(644) (Show Source): You can put this solution on YOUR website!

Find 3 odd consecutive integers such that the product of the first and third minus the middle integer is 338.
Ans:
Let the 3 odd integers be n-2,n and n+2
Product of 1st and 3rd = 
Subtracting middle integer

Or

This is a simple quadratic equation which can be solved by factorizing.


So possible solutions for n are  or 

Correspondingly, the 3 numbers are (-20,-18,-16) or (17,19,21)

Since is is not mentioned that the integers are positive, both solutions are valid.

Check: 

Both are correct!

:)

RELATED QUESTIONS
Find three consecutive odd intergers such that the product of the second and third minus... (answered by CubeyThePenguin)

Find three consecutive odd intergers such that the product of the first and the seconds... (answered by MathLover1)

Find three consecutive odd intergers such that three times the second minus the third is... (answered by checkley71)

Find three consecutive positive intergers such that the product of the first and second... (answered by htmentor)

find three consecutive odd positive intergers such that 2 times the sum of all three is... (answered by solver91311)

Find three consecutive odd positive intergers such that 5 times the sum of all three is... (answered by mananth)

Find three consecutive positive even intergers such that the product of the first and... (answered by Fombitz)

find three consecutive intergers such that the product of the second and third is... (answered by josmiceli,Alan3354)

find three consecutive odd intergers such that the second is 20 less than 3 times the... (answered by josgarithmetic,MathTherapy,ikleyn)