SOLUTION: This quadriatic problems just get to me and looking for an area is even more confusing. The question the teacher asks, not in the textbook is this: 1. You have 188 feet of

Question 84913This question is from textbook
: This quadriatic problems just get to me and looking for an area is even more confusing.
The question the teacher asks, not in the textbook is this:

1. You have 188 feet of fencing to enclose a rectangular region. What is the maximum area? This question is from textbook

Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
the perimeter (2L+2W) of the fence is 188, so L+W=94 ... and W=94-L ... so the area (L*W) is also L(94-L) or 94L-L^2

A=94L-L^2 is a downward opening parabola ... the maximum value for A lies on the axis of symmetry

the general equation for the axis of symmetry is x=-b/2a or in this case L=-94/-2 or L=47

A=94*47-47^2 ... A=2209 sq.ft.
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