SOLUTION: Find the possible values of d if real solutions exist for x² + 5x - 1
- d(x²+1) = 0
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Question 847477: Find the possible values of d if real solutions exist for x² + 5x - 1
- d(x²+1) = 0
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
After doing some distributive property you'll end up with this result.
-dx^2-d+x^2+5x-1 = 0
Let's group the x^2,x, and constant terms together like this:
(1-d)x^2 +5x +(-1-d)
From there we can satisfy our discriminant
<--- sorry I have to put that 0 in or the +- doesn't show
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