SOLUTION: 2y^2+4xy=x2=^2 Solve for y. I cannot figure out what to even do here what could the answer be?

Algebra.Com
Question 842018: 2y^2+4xy=x2=^2
Solve for y.
I cannot figure out what to even do here
what could the answer be?

Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
First, you need to correct the right hand side of the equation.
Please repost.

RELATED QUESTIONS

2y^2+4xy=x^2 Solve for y. I cannot figure out what to even do here what could the... (answered by Alan3354,jim_thompson5910)
Please solve algebraically: 2x^2 + 2y^2 + 4x = 6y x^2 + y^2 + 2x - 3y = 1 For the... (answered by jim_thompson5910)
I have tried to figure out how to properly graph this problem however, when I looked at... (answered by Fombitz,algebrapro18)
I cannot figure out how to do the equation 1/2(2y+3)=-2/3(y-4) I get different answers... (answered by lwsshak3)
(2/3)+(5/(y-4))=(y+6)/(3y-12). Solve the equation and check your solution. If there is no (answered by mananth)
Could someone please help me solve this problem: {{{x^2-y^2+4xy^2+4y^4}}} I tried... (answered by Nate,stanbon)
directions on worksheet--solve for y and graph equation *find solution* i cannot figure (answered by solver91311)
Could someone please help me out with this one? I am suppose to evaluate this expression... (answered by AnlytcPhil)
Please help me solve this: (2x^7y^2/4xy^3)^3 I do not even know where to begin. I am... (answered by Fombitz)