SOLUTION: 3x^2 + 2 1/2 x = -2 A x = {-5 +- i[SQRT(71)}/12 Bx = {5 +- i[SQRT(71)]}/12 Cx = {-2 +- i[SQRT(12)]}/7 Dx = {2 +- i[SQRT(17)]}/-7 E x = {-3 +- i[SQRT(17)]}/12 F x = {3

Question 841615: 3x^2 + 2 1/2 x = -2
A x = {-5 +- i[SQRT(71)}/12
Bx = {5 +- i[SQRT(71)]}/12
Cx = {-2 +- i[SQRT(12)]}/7
Dx = {2 +- i[SQRT(17)]}/-7
E x = {-3 +- i[SQRT(17)]}/12
F x = {3 +- i[SQRT(71)]}/-12
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

3x^2 + 2 1/2 x = -2 

3x^2 + 2 1/2 x + 2 = 0



  6x^2 + 5x + 4 = 0    |format:  a^2 + bx + c

 

 

 

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