SOLUTION: Find the standard equation of a parabola that has a vertical axis and satisfies the given conditions.
vertex (6, −5), x-intercept −1
Hi,
the vertex form of a Parabola opening up(a>0) or down(a<0),
where(h,k) is the vertex and x = h is the Line of Symmetry
vertex (6, −5), x-intercept −1 , P(-1,0) |using P(-1,0) to solve for 'a'
0 = 49a - 5