SOLUTION: Rewrite the middle term as the sum of two terms and then factor by grouping. x^2 – 2x – 63

Algebra.Com
Question 83967: Rewrite the middle term as the sum of two terms and then factor by grouping.
x^2 – 2x – 63

Answer by praseenakos@yahoo.com(507)   (Show Source): You can put this solution on YOUR website!
Question:

Rewrite the middle term as the sum of two terms and then factor by grouping.
x^2 – 2x – 63

Answer:

Here find out two numbers, whose sum is -2{that is coefficient of 'x' term and whose product is -63(that is constant term)

Such two numbers are -9 and +7
(
Now rewrite the given expression as follows...

x^2 - 9x + 7x - 63 = 0


Now group the terms...




(x^2 - 9x) + (7x - 63) = 0



Now take take out the common term from both the groups...



==> x( x-9) + 7(x-9) = 0


Now (x-9) is common in both the terms...



==> (x-9) (x-7)



So the factors of given expression are (x-9) and (x-7).



Hope you found the explanation useful....



Regards...



Praseena.









RELATED QUESTIONS

Rewrite the middle term as the sum of two terms and then factor by grouping. x^2 –... (answered by stanbon)
rewrite the middle term as the sum of two terms and then factor by grouping... (answered by jim_thompson5910)
Rewrite the middle term as the sum of two terms and then factor by grouping. x^2 +... (answered by stanbon)
rewrite the middle term as the sum of two terms and then factor by grouping... (answered by jim_thompson5910)
rewrite the middle term as the sum of two terms and then factor by grouping... (answered by checkley71)
Rewrite the middle term as the sum of two terms and then factor by grouping. x^2... (answered by chitra)
rewrite the middle term as the sum of two terms and then factor by grouping... (answered by dolly)
rewrite the middle term as the sum of two terms and then factor by grouping... (answered by jim_thompson5910,tutorcecilia)
rewrite the middle term as the sum of two terms and then factor by grouping... (answered by jim_thompson5910)