SOLUTION: Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadr

Question 839475: Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadratic equation. If the second quadratic equation is x^2+ax+b=0, find the value of a and b.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Given that the quadratic equation x^2-2x-5=0 has 2 different roots, and a second quadratic equation has 2 roots, each of which 2 less than the corresponding root of the given quadratic equation. If the second quadratic equation is x^2+ax+b=0, find the value of a and b.

(x-1) = +/- sqrt(6)

The roots of the second equation will be
,
sum of roots = -4
product of the roots = *
=-2
The general equation is
x^2-sum of roots(x)+product of the roots=0

comparing the equation with
x^2+ax+b=0
we get
a=4, b=-2
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