SOLUTION: The equation is h(t)= -16t^2+50t+4. (h for feet and t for seconds). The question is When will the ball be 40 feet above the ground. I plugged 40 into h(t), subtracted it and insert

Question 838361: The equation is h(t)= -16t^2+50t+4. (h for feet and t for seconds). The question is When will the ball be 40 feet above the ground. I plugged 40 into h(t), subtracted it and inserted it into the other side. I factored but got t=9/8 and t=2. I do not think I am supposed to have two positive numbers.
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
?
?

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discriminant is
, TWO POSITIVE VALUES.
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Continuing,
or
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What goes up also comes down.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The equation is h(t)= -16t^2+50t+4. (h for feet and t for seconds). The question is When will the ball be 40 feet above the ground. I plugged 40 into h(t), subtracted it and inserted it into the other side. I factored but got t=9/8 and t=2. I do not think I am supposed to have two positive numbers.
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Yes you are.
The ball starts at a height of 4 ft.
It rises at a rate of 50 ft/sec
It takes 9/8 = 1 1/8 seconds to reach a height of 40 ft because
gravity is pulling it down at 16 ft/(sec^2).
It continues to rise, then descends to a height of 40 ft.
after being in flight 2 seconds.
Cheers,
Stan H.
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