SOLUTION: Hi, So I didn't really understand how to do this problem and I was wondering if you could do it step by step so I could fully understand. Thanks so much for your time and effort.

Question 833706: Hi,
So I didn't really understand how to do this problem and I was wondering if you could do it step by step so I could fully understand. Thanks so much for your time and effort.
Question :
The equation for the motion of a projectile fired straight up at an initial velocity of 64ft/s is h=64t-16t^2, where h s the height in feet and t is the time in seconds. Fine the time the projectile needs to reach its highest point. How high will it go ?
Again thanks so much! c:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The equation for the motion of a projectile fired straight up at an initial velocity of 64ft/s is h=64t-16t^2, where h s the height in feet and t is the time in seconds. Fine the time the projectile needs to reach its highest point. How high will it go ?
---------------
h(t) = 64t-16t^2 is a parabola.
Max h is the vertex
t @ vertex = -b/2a = -64/-32 = 2 seconds
-------
Max h is h(2)
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