SOLUTION: What is the vertex of y=(2x-3)(2x+1). I'm confused on what to do when there's a number in front of the x

Question 830385: What is the vertex of y=(2x-3)(2x+1). I'm confused on what to do when there's a number in front of the x
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The vertex occurs for the x value between the roots, exactly in the middle.

The x intercepts are considered to be the roots.
(2x-3)(2x+1)=0
-
2x-3=0, then is one root
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2x+1=0, then is a root.
-
The x value at the exact middle of these is
-
What is the y coordinate where ?
Now you have your vertex, (x,y).
(Use the given equation for to find the corresponding y value).

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
What is the vertex of y=(2x-3)(2x+1). I'm confused on what to do when there's a number in front of the x

y = (2x - 3)(2x + 1)
------ FOILing the binomials
------ Formula for the x-coordinate of the vertex, with:
a being + 4, and b being - 4
------- Determining x-coordinate of vertex
x, or x-coordinate of vertex = , or
----- Substituting for x in quadratic equation

, or
Vertex: (,)
You can do the check!!
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