SOLUTION: solve for y the equation 3(y2+3)=28y.
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Question 826742: solve for y the equation 3(y2+3)=28y.
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
First of all, please use the "^" character (shift 6) to indicate exponents. Your equation should read:
3(y^2+3)=28y
To solve this we need it in standard form: . So we start by transforming the equation. First, simplify:
Subtract 28y:
Next, factor (or use the Quadratic Formula):
From the Zero Product Property:
3x-1 = 0 or x-9 = 0
Solving these we get:
or
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