SOLUTION: The area of a rectangular ping pong table is {{{45 feet^2}}}. The length is 4 feet longer than the width. Let x = the width. Find the length in feet.
So far I have {{{45x^2+4x=0
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Question 825846: The area of a rectangular ping pong table is . The length is 4 feet longer than the width. Let x = the width. Find the length in feet.
So far I have
Found 2 solutions by htmentor, josgarithmetic:
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
The area of a rectangle is length*width
Given: width = x, length, l = x+4
The area = x*(x+4) = 45
x^2+4x-45 = 0
This can be factored as (x-5)(x+9) = 0
Taking the positive solution, we have x = 5
Therefore, the length = 5+4 = 9 ft.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
L=length
L=x+4
x=width
Area,
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