SOLUTION: how would you put 2x^2-12+2x=(x-2)^2+2 in the standard form ax^2+bx+c=0

Question 825472: how would you put 2x^2-12+2x=(x-2)^2+2 in the standard form ax^2+bx+c=0
Found 2 solutions by unlockmath, josgarithmetic:
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
First we want to expand this 2x^2-12+2x=(x-2)^2+2 as:
2x^2-12+2x= x^2-4x+4+2
Now we can get everything on one side to look like this:
x^2+6x-18=0
Make sense?
RJ
www.math-unlock.com
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Another Complete-the-Square question!

'
The rectangular area being x accross x+6, is missing the square piece, .
'

, DONE.
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