SOLUTION: Evaluate A = {{{(a^2 − 3a +1)^2 − (1− a)(−2a +1)(1− 3a)}}} . Then WITHOUT doing any further calculation write down the value of B = {{{(a^2 + 3a +1)^

Question 823758: Evaluate A = AMP Parsing Error of [(a^2 − 3a +1)^2 − (1− a)(−2a +1)(1− 3a)]: Invalid expression. Closing bracket expected −3\a+1)^2−(1−a)(−2\a+1)(1−3\a) at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 187. . . Then WITHOUT doing any
further calculation write down the value of B = .
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Too much gibberish.
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SOLUTION: Evaluate A = {{{(a^2 &#8722; 3a +1)^2 &#8722; (1&#8722; a)(&#8722;2a +1)(1&#8722; 3a)}}} . Then WITHOUT doing any further calculation write down the value of B = {{{(a^2 + 3a +1)^

SOLUTION: Evaluate A = {{{(a^2 − 3a +1)^2 − (1− a)(−2a +1)(1− 3a)}}} . Then WITHOUT doing any further calculation write down the value of B = {{{(a^2 + 3a +1)^