Hi,

What is the ordered pair of the vertex of 

f(x)=x^2+8x+6

Using the vertex form of a parabola,  

where(h,k) is the vertex

f(x)=x^2+8x+6           |Putting into the vertex form by completing the square

f(x)= (x+4)^2 - 16 +6

f(x)= (x+4)^2 - 10     P(-4, -10) is the vertex



 

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