SOLUTION: Find the exact length of the side of a square whose diagonal is 3 feet.
This is what I have.
x^2 + x^2 = (x + 3)^2
x^2 + 4x + 9
x^2 - 4x - 9 = 0
x= 4 plus/minus sqrt 39 - 9(1
Algebra.Com
Question 81780: Find the exact length of the side of a square whose diagonal is 3 feet.
This is what I have.
x^2 + x^2 = (x + 3)^2
x^2 + 4x + 9
x^2 - 4x - 9 = 0
x= 4 plus/minus sqrt 39 - 9(1)(-4)/2(1)
6 + 9 sqrt (2)/2
= 6 + 3 sqrt (2)
Would appreciate any help with this question. Thank you
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since we know the diagonal is 3 feet we can use Pythagoreans theorem
and replace with 3 and with like this:
Square 3
Combine like terms
Divide both sides by 2
Take the square root of both sides
Reduce
Since a negative length doesn't make sense our only answer is
Check:
Plug in the leg into Pythagoreans theorem
Square each individual term
Add
Reduce
Take the square root of both sides
works. This verifies our answer.
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