SOLUTION: A ball is thrown from an initial height of 6 feet with an initial upward velocity of 33 feet per second. The ball's height h (in feet) after t seconds is given by the following.

Algebra.Com
Question 816417:
A ball is thrown from an initial height of 6 feet with an initial upward velocity of 33 feet per second. The ball's height h (in feet) after t seconds is given by the following.
h=6+33t-16t^2
Find all values of t for which the ball's height is 22 feet.
Round your answer(s) to the nearest hundredth.

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
22=6+33t-16t^2
t = 0.77930
t = 1.2832

RELATED QUESTIONS

A ball is thrown vertically upward from the ground with an initial velocity of 103 feet... (answered by ikleyn)
A ball is thrown vertically upward from the ground with an initial velocity of 103 feet... (answered by ikleyn)
the height of an object is given by s=-9t^2+vt+s0 where v is the initial velocity and s0... (answered by ikleyn)
A ball is thrown vertically upward with an initial velocity of 80 feet per second. The... (answered by Alan3354,ikleyn)
The height s of a ball, in feet, thrown with an initial velocity of 112 feet per second... (answered by ikleyn)
A ball is thrown from an initial height of 4 feet with an initial upward velocity of (answered by Boreal)
A ball is projected directly upward from and initial height of 200 feet with an initial... (answered by jorel1380,ikleyn)
A ball is thrown upward from a 100 foot tall building with an initial velocity of 14 feet (answered by ankor@dixie-net.com)
A ball is thrown upward from a height of 15 feet with an initial velocity of 5 ft/s. use... (answered by lwsshak3)