SOLUTION: -6 2/5 x2 + 7 1/5 x - 3 1/5 = 0
A x = {-2 +- i[SQRT(13)]}/2
Bx = {-6 +- i[SQRT(47)]}/16
Cx = {9 +- i[SQRT(21)]}/-2
Dx = {7 +- i[SQRT(126)]}/-2
E x = {-9 +- i[SQRT(47)]}/
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Question 814416: -6 2/5 x2 + 7 1/5 x - 3 1/5 = 0
A x = {-2 +- i[SQRT(13)]}/2
Bx = {-6 +- i[SQRT(47)]}/16
Cx = {9 +- i[SQRT(21)]}/-2
Dx = {7 +- i[SQRT(126)]}/-2
E x = {-9 +- i[SQRT(47)]}/-16
F x = {2 +- i[SQRT(126)]}/-6
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
-6 2/5 x2 + 7 1/5 x - 3 1/5 = 0
-------------
Multiply by 5 to eliminate fractions.
-5 might be better.
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